Question

a body start from initial velocity of 10 m/s and acceleration 5 m/s find distance covered in 5 second ​

Answer 1

Answer:

u = 0m/s

a = 5m/s^2

t = 5s

s ( distance ) = ?

s = ut + 1/2at^2

s = 0m/s * 5s + 1/2 * 5m/s^2 * (5s)^2

= 1/2 * 5m/s^2 * 25s^2

= 1/2 * 125m

= 62.5m

distance = 62.5m

hope it helps you