Question

A body start from rest, accelerated with 0.5 m/s2. Distance covered in 2 min time is

Answer 1

GIVEn

A body start from rest, accelerated with 0.5 m/s²

How many distance distance coved in 2minute

SOLUTIOn

• u = 0 {body started from rest}
• a = 0.5 m/s²
• t = 2 min = 2*60 = 120

Apply this formula

→ s = ut + ½ at²

→ s = 0*2 + ½ × 0.5 × (120)²

→ s = 0 + ½ × 0.5 × 120 × 120

→ s = 0.5 × 60 × 120

→ s = 3600 m

Hence, distance covered by body in 2min is 3600m

Answer 2

Given :-

Initial velocity of body (u) =0

Acceleration (a) =0.5m/s^2

Time (t) = 2min

=> 2×60 = 120 seconds

To find :-

Tue distance covered by body in the given time !

• Here We use 2nd equation of motion to fund the distance

$\bigstar{\boxed{\sf{s=ut+\dfrac{1}{2}at^2}}}$

$:\implies\sf s= 0\times (120) +\dfrac{1}{2}\times 0.5\times (120)^2\\ \\ :\implies\sf s= 0+ \dfrac{ 0.5\times \cancel{14400}}{\cancel2}\\ \\ :\implies\sf s= 0+ 0.5\times 7200 \\ \\ :\implies\sf s= 3600m\\ \\ \bullet\sf \ Convert \ In\ \ km\\ \\ :\implies\sf distance = 3.6km$

$\underline{\boxed{\textsf{ distance\ covered = {\textbf{3.6 \ km }}}}}$