Question

A body start from rest and acquries 12m\s in 2s calculate the acceleration and distance

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

The acceleration of the body is 6 m/s² and the distance covered by the body is 12 m.

Explanation:

The body starts from rest. So its initial velocity, u = 0.

The final velocity of the body is 12 m/s.

Time (t) taken for this change = 2 s

The acceleration of the body can be found using the 1st equation of motion.

    v = u + at

⇒ a = (v - u) / t

      = (12 - 0) / 2

∴  a = 6 m/s²

The distance covered by the body can be found using the 3rd equation of motion.

  v² = u² + 2as

⇒ s = (v² - u²) / 2a

      = (12² - 0²) / (2 × 6)

      = 144 / 12

∴ s  = 12 m