Question

A body start from rest and aquires a velocity of 12m/s in 5 second. calculate the acceleration and diatance moved .​​

Answer 1

Answer: Acceleration = 2.4 m/s^-2

Distance = 30m

Explanation: v = u + at

12 = 0 + 5a

a = 12/5 = 2.4 m/s^-2

s = ut + 1/2$at^{2}$

s = 0 + 1/2 * 2.4 *25 = 30m

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Answer 2

Answer:

initial velocity= 0

final velocity= 12m/s

Time= 5s

a=?;s= ?

using formula v= u+at

a=v-u

t

= 12-0/5

=12/5

= 2.4ms-²

s= ut+1/2at²

= 0+ 1/2× 2.4× 5²

=1.2× 25

=30 m

•°• acceleration= 2.4 ms-²

distance= 30 m