Question

A body start from rest and move with constant acceleration . The ratio of distance covered by body in nth second to that covered in n second

Answer 1

Answer:

Explanation:

For nth second,

x = u + 0.5a(2n – 1)

at rest u = 0

thus

x = 0.5a(2n-1)...................(1)

For n second,

y = 0 + 0.5an^2....................(2)

dividde the eqns,

x/y = (2n-1)/n^2