A body start from rest and moves with an acceleration of 2m/s2. find the distance travelled by the body in 10th seconds of motion
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Answer:
s=ut+1/2at2
s=0×10+1/2×2×10×10
s=200/2
s=100m
Answered by
0
Answer:
Initial velocity (u) = 0, as object is starting from rest; acceleration(a) = 2m/s^2; time = 10 sec
Distance (s) = ut + 1/2 at^2
s = (0 × 10) + 1/2 × 2 × (10)^2
s = 0 + 1 × 100
s = 0 + 100
s = 100m
Therefore,distance covered = 100m
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