Physics, asked by vinodvasu8068, 10 months ago

A body start from rest and moves with an acceleration of 2m/s2. find the distance travelled by the body in 10th seconds of motion

Answers

Answered by kss14
0

Answer:

s=ut+1/2at2

s=0×10+1/2×2×10×10

s=200/2

s=100m

Answered by Anonymous
0

Answer:

Initial velocity (u) = 0, as object is starting from rest; acceleration(a) = 2m/s^2; time = 10 sec

Distance (s) = ut + 1/2 at^2

s = (0 × 10) + 1/2 × 2 × (10)^2

s = 0 + 1 × 100

s = 0 + 100

s = 100m

Therefore,distance covered = 100m

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