Question

A body start from rest covers 50m in 10sec,it's Acceleration is(a)2m/s2(b)1m/s2(c)0.5m/s2(d)0.25m/sec power2​

Answer 1

Answer

Given :-

• Initial velocity (u) = 0 m/s (as it is given body starts from rest)
• Distance covered (s) = 50 m
• Time taken (t) = 10 sec

To find :-

• Acceleration - a

Solution :-

• u = 0 m/s
• s = 50 m
• t = 10 sec

Substituting the value in 2nd equation of motion :-

⟹ $\boxed{\sf s = ut + 1/2 at^2}$

⟹ $\sf 50 = 0 + \frac{1}{2} \times a \times 10^2$

⟹ $\sf 50 = \frac{1}{\cancel 2} \times a \times \cancel {100}$

⟹ $\sf 50 = 50a$

⟹ $\sf a = \frac{\cancel {50}}{\cancel {50}}$

⟹ $\sf a = 1 m/s^2$

$\boxed{\rm\red{Acceleration = 1 m/s^2 }}$

Answer 2

Solution :-

Given :-

• Initial Velocity (u) → 0 m/s
• Distance (s) → 50 m
• Time (t) → 10 s

To Find :-

• Acceleration

Formula Used :-

• $\pink{ \underline{\underline{ \green{ \boxed{ \red{ \rm s = ut + \frac{1}{2} a t^{2}}}}}}}$

$\gray{\rm \longrightarrow 50 = 0 + \dfrac{1}{2} \: a \: {10}^{2} }$

$\gray{\rm \longrightarrow 50 = \cancel{\dfrac{1}{2} \times 100} \times a}$

$\gray{\rm \longrightarrow 50 = 5a}$

$\gray{\rm \longrightarrow a = \cancel{\dfrac{50}{50} }}$

$\gray{\rm \longrightarrow a = 1 }$

$\purple{\underbrace{\tt Thus, \: (b) \: 1 m/s^{2}}}$

Additional Information

• The SI unit of Acceleration is m/s²
• SI unit of time is second
• SI unit of distance is metre

The laws of Motion :-

• v = u + at
• s = ut + ½ at²
• v² - u² = 2as