Question

A body start from rest.what is the ratio of distance travelec by the body during fourth and third second

Answer 1

$\textbf{ Hello Mate! }$

s = ut + 1/2 (at² )

As object started from rest so u = "0"

s = (0)(t) + 1/2(a)(4)²

s = 16a/2

s = 8a

Next, s' = (0)(t) + 1/2(a)(3)²

s' = 9a/2

s : s' = 8a / ( 9a / 2 )

= 16 / 9 or 16 : 9

$\boxed{ Answer = 16 \: : \: 9 }$

Have great day ahead!