Physics, asked by puneethk5921, 1 year ago

A body start from rest what is the ratio of the distance travelled by the body during the 4th and 3 rd secound

Answers

Answered by Anonymous
2

Hi friend,


The formula is


Sn= u+a/2(2n-1)


For t=n=3


S3= 0+10/2(5)

S3= 50/2 m


Similarly,


S4= 0+10/2(7)


S4= 70/2m


S3/S4= 50/2×2/50


S3:S4= 5:7


Hope this helped you a little!!!!

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