Question

A body start from rest with a
uniform acceleration 2m s- Find the
distance covered by the body in 2 s



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Answer 1

Given:-

• Initial velocity ,u = 0m/s
• Acceleration ,a = 2m/s²
• Time taken ,t = 2s

To Find:-

• Distance Covered ,s

Solution:-

According to the Question

we have to calculate the the distance covered by body in 2s.

Using 2nd equation of motion

☯ s = ut+1/2at²

where,

• s denote distance
• a is the acceleration
• u is the initial velocity
• t is the time taken

Substitute the value we get

$\longmapsto$ s = 0×2 + 1/2×2 ×2²

$\longmapsto$ s = 0 + 2²

$\longmapsto$ s = 4m

• Hence, the distance covered by the body is 4 metres.

Answer 2

Answer:

Distance = 4m

Step-by-step explanation:

Data:-

• a = 2m/s^2
• u = 0m/s (as the body starts from rest)
• t = 2s

To find:-

• Distance covered = s = ?

Formula:-

• $s = ut + \frac{1}{2} a {t}^{2}$

Solution:-

1. $s = 0 \times 2 + \frac{1}{2} \times 2 \times {(2)}^{2}$
2. $= 0 + \frac{1}{2} \times 2 \times 4$
3. $= \frac{8}{2 } = 4m$