Question

a body start from the origin with an acceleration of 6 m/s2 along the X- axis and 8 m/s2 along the y-axis.its distance from the origin after 4 second will be :

Answer 1

Answer:

S= ut + (1/2)at? t = 4 sec S = 0 + (1/2)a(4)² S= 8a a = 6m/s? x & 8m/s? y lal = v(62 + 8?) = v(36+64) = v100 = 10 S= 8*10 = 80 m 80 m is the distance Please mark the answer as "The Brainliest answer" if you like it