Question

A body started from rest and advanced with uniform acceleration 5/ms^ what is the velocity after 3 second? ​

Answer 1

Answer:

u=0,a (uniform acceleration),t=n

v (final velocity after n seconds)

v=0+an⟹v=an⟶(1)

s

n

(distance travelled in n seconds)=0+

2

1

an

2

s

n−2

=

2

1

a(n−2)

2

Distance travelled in least 2 seconds =s

n

−s

n

−2

=

2

1

a[n

2

−(n−2)

2

]=

2

1

a[n

2

−n

2

−4+4x]=2an−2a⟶(2)

From equation 1 and 2,

x=2a(n−1)

x=

u

2v

(n−1)

Hope this will help you..

Answer 2

Answer:

Initial velocity= 0 = u

Acceleration= 5 m/s = a

Time= 3 seconds = t

Solution:

Using first equation of motion,

v = u+at

v = 0+(5×3)

v = 15 m/s

.°. The velocity after 3 seconds is 15m/s.

Glad to help you..