Question

a body started from rest and is moving with uniform acceleration of 10 metre per second square find the time in which it covers a distance of 45 metres​

Answer 1

Answer:

Given:

Initial velocity = 0 m/s

Acceleration = 10 m/s²

Distance covered = 45 m

To find:

Time taken .

Formulas used:

$s \: = ut \: + \frac{1}{2} a {t}^{2}$

s ----> displacement,

u -----> initial velocity

a ------> acceleration

t -------> time

Calculation:

s = ut + ½at²

=> 45 = 0 × t + ½ × 10 × t²

=> 5t² = 45

=> t² = 9

=> t = 3 seconds.

Final answer is 3 seconds.

Answer 2

$\huge{\underline{\underline{\red{\mathfrak{Answer :}}}}}$

Given :

• Acceleration (a) = 10 m/s²

• Initial velocity (u) = 0 m/s

• Distance Travelled (s) = 45 m

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To Find :

Time Interval

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Solution :

We have formula :

$\Large{\underline{\boxed{\red{\sf{S \: = \: ut \: + \: \frac{1}{2} \: at^2}}}}}$

Where,

S is Distance travelled

u is initial velocity

a is acceleration

t is time interval

_____________[Put Values]

⇒ 45 = (0)(t) + ½ (10)(t)²

⇒45 = 0 + ½(10t²)

⇒45 = 5t²

⇒t² = 45/5

⇒t² = 9

⇒t = √9

⇒t = 3 s

$\Huge{\underline{\boxed{\sf{Time \: = \: 3 \: s}}}}$

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Addition Information :

• First Equation of Motion , v = u + at

• Second Equation of Motion , v² - u² = 2as

• Third equation of motion, S = ut + ½at²

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