Question

A body started from rest and moved with acceleration 2 ms-2 for 5s. Then it moved with the acquired velocity for
5s. It was retarded and brought to rest in 5s. Find the total distance covered by it.​

Answer 1

Answer:

Explanation:

CASE 1

U=0

a=2m/s²

V=10m/s

S=10 m

CASE 2

U=10m/s

V=0m/s

T=5s

a=-2m/s²

S=25m

Total distance=10+25= 35