Question

A body started from rest moving with an acceleration of 4m/square. find the time taken by the body to displace by 50m

Answer 1

Answer:

u= 0 m/s

a= 4 m/s²

s= 50m

Formula-

s=ut + 1/2at²

50=0xt + 0.5x4xt²

50=2 x t²

t²=50/2

t= √25

t=5 seconds

Answer 2

Answer:

• The time taken (t) by the body is 5 Seconds.

Given:

1. Acceleration of particle (a) = 4 m/s².
2. Displacement covered (S) = 50 m

Explanation:

$\rule{300}{1.5}$

From Second kinematic equation we know,

⇒ S = u t + 1 / 2 a t²

Where,

• S Denotes Distance travelled.
• u Denotes Initial velocity.
• t Denotes Time period.
• a Denotes acceleration.

Now,

⇒ S = u t + 1 / 2 a t²

Substituting the values,

⇒ 50 = 0 × t + 1 / 2 × 4 × (t)²

⇒ 50 = 0 + 1 / 2 × 4 × t²

⇒ 50 = 1 / 2 × 4 × t²

⇒ 50 = 2 × t²

⇒ 50 / 2 = t²

⇒ t² = 50 / 2

⇒ t² = 25

⇒ t = √ 25

⇒ t = 5

⇒ t = 5 sec.

∴ The time taken (t) by the body is 5 Seconds.

$\rule{300}{1.5}$