A BODY STARTED FROM REST REACHED AT A VELOCITY OF 25 m/s IN 5 sec .FIND THE ACCELERATION
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initial velocity=0m/s (body started from rest),
final velocity=25m/s
time=5s
A=v-u/t
=25-0/5
25/5
5m/s^2=Acceleration
final velocity=25m/s
time=5s
A=v-u/t
=25-0/5
25/5
5m/s^2=Acceleration
insiyahr:
THANKS DEAR
Answered by
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hi friend
here is your answer
-----------------------------------------------------------------------------------------------------------------
here
u= 0m/s
v= 25m/s
t= 5 sec
so a= (v-u)/t
a=( 25-0)/5
a= 25/5
a=5m/s^2
so the acceleration will be the 5 metre per second square.
hope this is helpful to you so please mark my answer as a brainliest
here is your answer
-----------------------------------------------------------------------------------------------------------------
here
u= 0m/s
v= 25m/s
t= 5 sec
so a= (v-u)/t
a=( 25-0)/5
a= 25/5
a=5m/s^2
so the acceleration will be the 5 metre per second square.
hope this is helpful to you so please mark my answer as a brainliest
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