Question

A body starting from rest accelerate uniformly at the rate of 100m/s-2 for 10 seconds. Calculate the final velocity at the end of 10 seconds and the distance travelled during this interval.​

Answer 1

Answer:

u=0

a=100m/s^2

t=10 s

v=?

s=?

Explanation:

v=u+at

v=0+100[10]

v=1000m/s

s=ut+1/2 at^2

s=0[10]+1/2 [100][10][10]

s=1/2[10000]

s=5000 m

Thank you

hope it helps !!!

have a nice day

Answer 2

Given :-

• Initial Velocity = 0 m/s
• Time = 10 seconds
• Acceleration = 100 m/s²

To Find :-

• Final Velocity of that body = ?
• Distance travelled by the body = ?

Answer :-

• Final Velocity of that body = 1000 m/s
• Distance travelled by the body = 5000 m

Explaination :-

First of all we will find the Final Velocity of the body by using first equation of motion :

• v = u + at

Where, v is Final Velocity , u is Initial Velocity , a is Acceleration and t is time taken.

Now, Substitute the given values in above equation :

➻ v = 0 + 100 × 10

➻ v = 100 × 10

➻ v = 1000 m/s

Now,let's calculate the distance travelled by the body by using second equation of motion :

• s = ut + ½ at²

Where, s is Distance , u is Initial Velocity, a is Acceleration and t is time taken.

Now, subsitute the given values in second equation of motion :

➺ s = 0 × 10 + ½ × 100 × 10 × 10

➺ s = ½ × 100 × 10 × 10

➺ s = 100 × 10 × 5

➺ s = 1000 × 5

➺ s = 5000 m

Hence,

• Final Velocity of that body = 1000 m/s
• Distance travelled by the body = 5000 m