Question

A body starting from rest accelerate uniformly at the rate of 100m/s-2 for 10 seconds. Calculate the final velocity at the end of 10 seconds and the distance travelled during this interval.​

Answer 1

Answer:-

→Final velocity = 1000m/s

→Distance travelled = 5000m

Explanation:-

Given:-

→Initial velocity if the body (u) = 0

[as it starts from rest]

→Acceleration (a) = 100m/s²

→Time (t) = 10 seconds

To find:-

→Final velocity at the end of 10s.(v)

→Distance travelled in given time

interval.(s)

Solution:-

By using the 1st equation of motion,

we get :-

=> v = u+at

=> v = 0+100(10)

=> v = 1000m/s

Now, by using the 2nd equation of motion,we get :-

=> s = ut+1/at²

=> s = 0(t)+1/2×100×(10)²

=> s = 50×100

=> s = 5000m

Thus:-

•Final velocity after 10s is 1000m/s.

•Distance travelled is 5000m.

Answer 2

$\huge \bf AnSwEr :$

Initial velocity if the body is at rest

Acceleration of the body is 100m/s²

Time taken by the body is 10sec

To find, Final velocity at the end of 10sec and Distance travelled

Solution:-

By using the 1st equation of motion,

➝ v = u+at

➝ v = 0+100(10)

➝ v = 1000m/s

hence, final velocity of the body is 100m/s

Now, by using the 2nd equation of motion,

➝ s = ut+1/at²

➝ s = (0)(t)+1/2(100)(10)²

➝ s = 50×100

➝ s = 5000m

hence, distance travelled by the body is 5000m