A body starting from rest acquires a velocity of 10 m/s in 5 seconds. Calculate (a) the acceleration (b) the distance covered by the body in 5 seconds.
Answers
Given :-
A body starting from rest acquires a velocity of 10 m/s in 5 seconds.
To Find :-
(a) the acceleration (b) the distance covered by the body in 5 seconds.
Solution :-
We know that
a = v - u/t
a = 10 - 0/5
a = 2
Acceleration is 2 m/s²
Now
v² = u² + 2as
(10)² = (0)² + 2(2)(s)
100 = 0 + 4s
100 = 4s
100/4 = s
25 = s
Hence
Distance is 25 m
➤ Answer
- Acceleration = 2m/s²
- Distance travelled by the body = 25 meters.
➤ Given
- A body starting from rest acquires a velocity of 10m/s in 5 seconds.
➤ To Find
- The acceleration of the body.
- Distance covered by the body in 5 seconds.
➤ Step By Step Explanation
Given a body starting from rest acquires a velocity of 10m/s in 5 seconds. We need to find the acceleration and the distance covered by the body in 5 seconds.
So let's do it !!
➠ By using first equation of motion.
- v = u + at
Substituting
=> 10 = 0 + a × 5
=> 10 = 5a
=> 10/5 = a
=> 2m/s² = a
Therefore, acceleration = 2m/s²
➠ By using third equation of motion
- v² - u² = 2as
Substituting
=> ( 10 )² - 0² = 2 × 2 × s
=> 100 = 4s
=> 100/4 = s
=> 25 m = s
➵ Therefore, distance travelled by the body = 25 meters.