Question

a body starting from rest acquires a velocity of 10 metre per second in 5 seconds calculate (a) acceleration (b) the distance covered by the body in 5 seconds what is the answer of this question​

Answer 1

$\displaystyle\sf{Given\:,}$

• $\displaystyle\sf{Velocity\:(v)=10\:m/s}$

• $\displaystyle\sf{Time\:(t)=5\:s}$

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$\displaystyle\sf{(a)}$

$\boxed{\displaystyle\sf{Acceleration\:(a)=\frac{Velocity\:(v)}{Time\:(t)}}}$

$\displaystyle\sf{Applying\:the\:values\:to\:the\:equation\:,}$

$\implies\displaystyle\sf{a=\frac{10}{5}}$

$\implies\displaystyle\sf{a=2\:m/s^2}$

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$\displaystyle\sf{(b)}$

$\boxed{\displaystyle\sf{Distance\:(d)=Velocity\:(v)\times Time\:(t)}}$

$\displaystyle\sf{Applying\:the\:values\:to\:the\:equation\:,}$

$\implies\displaystyle\sf{d=10\times5}$

$\implies\displaystyle\sf{d=50\:m}$

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$\boxed{\displaystyle\sf{(a)\:Acceleration=2\:m/s^2}}$

$\boxed{\displaystyle\sf{(b)\:Distance=50\:m}}$