Question

A body starting from rest acquires a velocity of 10m/s in 5 seconds calculate the acceleration and the distance covered by the body in 5 seconds

Answer 1

Step-by-step explanation:

The initial velocity is

u

=

0

m

s

−

1

The acceleration is

a

=

10

m

s

−

2

The time is

t

=

5

s

Apply the equation of motion

v

=

u

+

a

t

The velocity is

v

=

0

+

10

⋅

5

=

50

m

s

−

1

The distance travelled in the first

5

s

is

s

=

u

t

+

1

2

a

t

2

=

0

⋅

5

+

1

2

⋅

10

⋅

5

2

=

125

m

The distance travelled in the following

10

s

is

s

1

=

v

t

1

=

50

⋅

10

=

500

m

The total distance travelled is

d

=

s

+

s

1

=

125

+

500

=

625

m

Answer link

Answer 2

Answer:

A body starting from rest acquires a velocity of 10m/s in 5 seconds calculate the acceleration and the distance covered by the body in 5 seconds