Question

A body starting from rest acquires the velocity of 50m/s . Calculate the distance covered by the body in 5 seconds.

Answer 1

Answer:

The distance covered by the body in 5 seconds is 125 m

Explanation:

Given :

A body starting from rest acquires the velocity of 50 m/s

To find :

the distance covered by the body in 5 seconds

Solution :

initial velocity, u = 0

final velocity, v = 50 m/s

time taken, t = 5 sec

distance covered, s = ?

Applying v = u + at,

50 = 0 + a(5)

50 = 5a

a = 50/5

a = 10 m/s²

The acceleration of the body is 10 m/s²

Now, applying v² - u² = 2as,

50² - 0² = 2 × 10 × s

2500 = 20s

 s = 2500/20

 s = 125 m

Therefore, the distance covered by the body in 5 seconds is 125 m