Question

A body starting from rest and moving with a constant acceleration,covers 10m in the first second the distance travelled in second second is?

Answer 1

Answer:

we have to add 10plus 10 per second

Answer 2

Question: A body starting from rest and moving with a constant acceleration, covers 10m in the first second. Find the distance travelled in the second second?

Solution: Using the equation for the distance travelled in the $n^{th}$ second,

$x_n=u+\frac{a}{2} (2n-1)$

We have, for the first second,

$10=0+\frac{a}{2} (2\times1-1) =\frac{a}{2} \\or,\: a=20m/s^{2}$

The distance travelled in the second second is,

$x_2=0+\frac{20}{2} (2\times2-1)=30m.$

→ Point to Note: Following this procedure, it can be shown that the distances travelled in successive equal time intervals will be in the ratio 1 : 3 : 5 : 7 .....