Question

A body, starting from rest and moving with a constant acceleration, covers 10 m in the first second. The distance travelled by it in the 2nd second is [ ] a) 19 m b) 10 m c) 20m d) 30 m
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Answer 1

Answer:

The distance traveled by the body in the 2nd second is 30 m.

Explanation:

The body is starting from rest. So its initial velocity, u = 0 m/s

Distance covered by the body, S = 10 m

Time taken to cover this distance, t = 1 s

The constant acceleration of the body can be found using the 2nd equation of motion.

S = ut + (at²/2)

⇒ a = (S - ut) × (2/t²)

      = (10 - 0) × (2/1²)

   a = 20 m/s²

Now the distance traveled by the body in 2 seconds can be found as:

S = ut + (at²/2)

S = 0 + (20 × 2²)/2

S = 40 m

So the distance traveled by the body in the 2nd second will be:

Distance traveled in 2 seconds - distance traveled in 1st second

40 - 10 = 30 m

Answer 2

Answer:

answer is in the attach. this is not my writing.

Explanation:

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