Question

A body starting from rest covers a distance of 0.45km and acquires a velocity of 300km/h it's acceleration will be

Answer 1

GiveN :

• Distance Travelled (s) = 0.45 km
• Initial velocity (u) = 0 m/s
• Final velocity (v) = 300 km/h

To FinD :

• Acceleration of the body

SolutioN :

Use 3rd equation of motion :

$\implies$ v² - u² = 2as

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$\implies$ 300² - 0² = 2 × 0.45 × a

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$\implies$ 90000 = 0.9 * a

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$\implies$ a = 90000/0.9

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$\implies$ a = 100000

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$\underline{\rm{\therefore \: Acceleration \: of \: body \: is \: 100000 \: kmh^{-2}}}$