Question

A body starting from rest has an acceleration of 0.1 m-2. Calculate the distance travelled in 5s.

Answer 1

Use second rquation of motion:

s = ut + ½at²

Given:

• initial velocity = u = 0 (at rest)
• acceleration = a = 0.1 m/s²
• time = t = 5s
• distance travelled = s = ?

Solution

• s = ut + ½at²
• s = 0(5) + ½ (0.1)(5)²
• s = 0 + ½ × 0.1 × 5×5
• s = 2.5/2
• s = 1.25 m

★ distance travelled in 5s is 1.25 m