Question

A body starting from rest has an acceleration of 0.3m/s2. calculate the velocity and distance travelled by it in 2 minutes.

Answer 1

velocity = 36 m/s
distance = 2060 m
see the above image for explanation.

Answer 2

Given :

Initial velocity of body , u = 0 m/s .

Acceleration of body , $a=0.3\ m/s^2$ .

To Find :

The velocity and distance travelled by it in 2 minutes i.e 120 seconds .

Solution :

Velocity and displacement is given by equation of motion .

$v=u+at\\v=0+0.3\times 120\\v=36\ m/s$

Also ,

$s=ut+\dfrac{at^2}{2}\\\\s=0+\dfrac{0.3\times 120^2}{2}\\\\s=2160\ m$

Therefore , the velocity and distance travelled by it in 2 minutes is 36 m/s and 2160 m respectively .

Learn More :

Kinematics

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