Question

A body starting from rest has an acceleration of 20 ms-2. The distance travelled by it in the 6th second will be ___

Answer 1

Answer:

$\boxed{\mathfrak{Distance \ travelled = 110 \ m}}$

Explanation:

From equation of motion we have:

$\boxed{ \bold{s_{n^{th}} = u + \frac{1}{2} a(2n - 1)}}$

$\rm s_{n^{th}}$ → Distance travelled in $\rm n^{th}$ second

According to the question,

Initial velocity (u) = 0 m/s (Starts from rest)

Accelration (a) = 20 m/s²

Time (n) = $\rm 6^{th}$ second

By substituting values in the equation we get:

$\rm \implies s_{n^{th}} = 0 + \frac{1}{2} \times 20(2 \times 6 - 1) \\ \\ \rm \implies s_{n^{th}} =10(12 - 1) \\ \\ \rm \implies s_{n^{th}} =10 \times 11 \\ \\ \rm \implies s_{n^{th}} =110 \: m$