A body starting from rest has an acceleration of 5m/s2. calculate the distance travelled by it in 4th second.
Answers
Answered by
63
HEYA..
U = 0
A = 5M/S^2
TIME = 2 S
THEREFORE DISTANCE , S= UT + 1/2 AT^2
[BY 2ND LAW OF MOTION]
S = 0* 4 + 1/2 * 5 * 4 * 4
S = 40 M...
THEREFORE DISTANCE IS 4O M
U = 0
A = 5M/S^2
TIME = 2 S
THEREFORE DISTANCE , S= UT + 1/2 AT^2
[BY 2ND LAW OF MOTION]
S = 0* 4 + 1/2 * 5 * 4 * 4
S = 40 M...
THEREFORE DISTANCE IS 4O M
Answered by
188
A = 5m/s^2
U = 0m
T=3s
S=ut+1/2at
S= 7.5m
Case 2
A=5m/s^2
U=0m
T=4s
S=u+1/2at
S=10m
Add both
S= 17.5m
U = 0m
T=3s
S=ut+1/2at
S= 7.5m
Case 2
A=5m/s^2
U=0m
T=4s
S=u+1/2at
S=10m
Add both
S= 17.5m
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