Question

A body starting from rest has an acceration of 5m/s^2 calculate the distance trevelled by it in 4 second

Answer 1

Answer:

acceleration= 5 m/s°2

intial velocity = 0 m/s

time = 4 s

Explanation:

using formula s=ut+at^2/2

s=0×5+5×4×4/2

distance travelled= 40m

Answer 2

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Given :-

Initial Velocity (u) = 0

acceleration (a) = 5m/s²

Time (t) = 4 sec

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To Find :-

Distance travelled (s)

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Solution :-

We have equation

$\LARGE{\boxed{\boxed{\sf{s \: = \: ut \: + \: \frac{1}{2} \: \times \: at^2}}}}$

_____________[Put Values]

s = 0 + 1 × 5 × (4)² / 2

s = 0 + 5 × 16 / 2

s = 80/2

s = 40

$\LARGE{\sf{s \: = \: 40 \: m}}$

•°• It travels 40 m