Physics, asked by muskanverma37, 8 months ago


A body starting from rest has on acceleration of 20m/sec^2
Calculate the distance travelled by it in
of
6th sec.​

Answers

Answered by raushan6198
2

Explanation:

a =20m/s^2

u =0m/s

n =6

Distance traveled in nth seconds is given by

s = u \:  +  \frac{a}{2} (2n - 1)

S = 0 + 20/2 ×(2×6 - 1)

S =10 ×(12 - 1)

S = 10× 11

S = 110 m

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