Question

A body starting from rest moves a distance 5/9th of the total distance in last sec its acceleration is 5m/s. Find total time,total distance,displacement in the last second and final velocity

Answer 1

Answer:

ANSWER

Given that,

The acceleration a=8m/s

2

Initial velocity u=0m/s

We know that,

The displacement in the nth second

=u+a(n−

2

1

)

Now, the displacement in 5th second

=0+8(5−

2

1

)

=36m

Hence, the distance covered by it in fifth second is 36 m