Question

A body starting from rest moves with a constant acceleration . it moves a distance s1 in first 5 seconds and a distance s2 in next 5 seconds. prove that triangle S2 =3s1​

Answer 1

Answer:

v=5a

S1=25a/2

S2=25a+25a/2=75a/2

S1×75a/2=S2×25a/2

S2=3S1,. hence proved

Explanation:

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