Question

A body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the 5th sec to that covered in 5sec is

Answer 1

Answer:

9:25

Explanation:

We know that distance is calculated as

S=ut+1/2at^2

Also, given that initial speed, u=0

So distance travelled in 5 sec is

S=1/2a(5)^2

Similarly in 4 sec will be

S=1/2a(4)^2

So distance travelled In 5th sec will be

S1={1/2a(5)^2} - {1/2a(4)^2}

So ratio of S1:S will be 9:25

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