Question

A body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the 5th second to that covered in 5 seconds is

Answer 1

Answer:

Distance covered in nth second

S = u + a(n - 0.5)

In 5th second

S₁ = 0 + a(5 - 0.5)

S₁ = 4.5a

Distance covered in t seconds

S = ut + 0.5at²

In 5 seconds

S₂ = 0 + (0.5 × a × (5 s)²)

S₂ = 12.5a

S₁ / S₂ = 4.5a / (12.5a)

= 9 / 25

Ratio of distance travelled in 5th second to 5 seconds is 9 : 25.

Answer 2

Hope it helps you and solves the problem. Sorry but I took help from my previous same answer.