Question

A body starting from rest moving with an acceleration of 5m/s2 acquires a velocity of 10m/s the the distance traveled by the body is​

Answer 1

initial velocity = 0 m/s

final velocity = 10 m/s

acceleration = 5 m/s²

we need time for finding the distance.

a = (v-u)/t

5 = 10/t

t = 10/5

t = 2 s

s = ut + 1/2 at²

s = 0 + 1/2 × 5 × 4

s = 10 m

therefore, the distance covered by the body is 10 m

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Answer 2

The distance travelled by body is 10 m.

Given - Acceleration, velocity

Find - Distance travelled

Solution - We will use third equation of motion to find the distance travelled.

v² - u² = 2aS, where v is final velocity, i is initial velocity, a is acceleration and S is distance.

Keep the values in formula to find the value of distance travelled.

${10}^{2} - {0}^{2} = 2 \times 5 \times S$

$100 = 10 \times S$

$S = \frac{100}{10}$

S = 10 m

Therefore, the distance travelled is 10 m.

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