Question

a body starting from rest moving with uniform acceleration has a displacement of 16m in first 4s and 9m in first 3s. find acceleretion of the body.?

Answer 1

we can use the equation of motion :
$s \: = ut \: + \frac{1}{2} a {t}^{2}$
s stands for distance, t for time, u for initial velocity, a for acceleration. as it began from rest, u = 0. So
$16 = (0 \times 4) + \frac{1}{2} a {4}^{2}$
from which we get a = 2(metres per second squared)

Answer 2

The acceleration of the body is $2\ m/s^2$.

Explanation:

It is given that,

Displacement, d = 16 m

Time, t = 4 s

Displacement, d' = 9 m

Time, t' = 3 s

Initial speed of the body, u = 0

Let a is the acceleration of the body. Using the second equation of motion as :

$d=ut+\dfrac{1}{2}at^2$

$16=0+\dfrac{1}{2}a(4)^2$

$a=2\ m/s^2$

Similarly,

$d'=ut+\dfrac{1}{2}at'^2$

$9=0+\dfrac{1}{2}a(3)^2$

$a=2\ m/s^2$

So, the acceleration of the body is $2\ m/s^2$. Hence, this is the required solution.

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Acceleration

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