Question

A body starting from rest rest travels with uniform acceleration if it travels 100m in 5s. what is the value of acceleration

Answer 1

initial velocity = 0m/s
s ( distance travelled ) = 100m
time = 5sec
acceleration = to be found

using second equation of motion
s = ut +1/2at²
100 = 0(5)+1/2(a)(5)²
100 = 0+25a/2
200 = 25a
a = 200/25 => 8m/s²
hope this helps

Answer 2

u = 0
S = 100m
t = 5s
a = ?

by second equation of motion,

S = ut + 1/2 at square
100 = 1/2 * a * 25
100 = 25/2 * a

Therefore,
a = 8m/s square.