Question

a body starting from rest starts running and attains a velocity of 6m s^-1 in 30 second . Then he slows down uniformly to 4m s^1 in next 5 s calculate his acceleration in both cases.​

Answer 1

Answer:

a = 0.2m/s²

a = -0.4m/s²

Given:-

CASE 1:

u = 0

v = 6

t = 30 sec

a = v-u / t

= 6-0/ 30

= 0.2 m/s²

CASE 2:

Now, speed slows down

 u = 6 m /s

v = 4 m/s

t = 5s

a = v-u/t

= 4 -6/5

=( - 0.4 m/s²)

The negative accelerated shows that the body is retarded.

I HOPE THIS WILL HELP YOU OUT :)