Question

A body starting from rest traveles for 30sce determine final velocity attined after a distance of 40m?

Answer 1

Answer:

Explanation: lets write the given data first...

u=0m/s(body is in rest)

v=v(let it be v to be determined)

s=40m

t=30 sec

using 2nd equation of motion i.e

s=ut+½at²

40=½ a×30×30

solving it, we'll get a=4/45m/s²-------1

putting it in first equation of motion i.e v=u+at

v=4/45×30 (from 1)

v=8/3

hence v=8/3 m/s or 2.6m/s(approx)

hope it helps!!

Answer 2

Answer:

S=Ut + 1/2at^2

Explanation:

S=40m

u =0 because it starts from rest

t=30s

a=?

Using above

40=450a

a=4/45

From these Use v=u+at

v=4/45* 30

v= 8/3