Question

A body starting from rest travels with uniform acceleration. If it travels 100 m in 5 sec, what is the value of acceleration?​

Answer 1

Answer:

Initial velocity = u = 0

distance traveled = s = 100 m

Time = t = 5 sec

a = acceleration

Equation of motion :-

s = ut + 1/2at²

= 0 + 1/2 a × 5 × 5

100 = 1/2a × 25

1/2a = 100 / 25

1/2a = 4

a = 4 × 2

= 8 m/s²

Answer 2

Answer:

A body starting from rest travels with a uniform acceleration. If it travels 100m in 5 seconds, what is the value of acceleration?

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The body or a man starts from rest meaning thereby that its initial speed is zero.

so under the action of some agency body gets velocity or say got accelerated

imagine that its speed/velocity changes per sec under the external action.

if a is acceleration in m/s^2 means in each second during its motion it will get its velocity increased by a m/s.

the displacement of the body say in a time interval dt

will be v.dt but v is increasing v= u +a.t

ds = (u +at)dt as u=0

ds = a.t.dt ,

if we add up displacements or integrate the left and right side from t=0 to t=t seconds we get distance covered s

s = (1/2) a. t^2

so here we are given the distance travelled s = 100 m and time t= 5 s

so, the acceleration a = {2 .100 m| /{ 25 s^2} = 8 m/s^2.

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