Question

A body starting from rest travels with uniform acceleration. If it travels 200 m in 10 s, then the
value of the acceleration is_______m/s.
​

Answer 1

Answer:

• The acceleration (a) is 4 m/s²

Given:

1. Distance (S) = 200 m.
2. Time (t) = 10 secs.
3. Initial velocity (u) = 0 m/s.

Explanation:

$\rule{300}{1.5}$

From second kinematic equation we know,

$\bigstar\;\underline{\boxed{\sf S=ut+\dfrac{1}{2}\;at^{2}}}$

Here,

• u Denotes initial velocity.
• t Denotes time.
• a Denotes acceleration.

Substituting the values,

$\longrightarrow\sf S=0\times 10+\dfrac{1}{2}\times a \times (10)^{2}\\\\\\\longrightarrow\sf S=0+\dfrac{1}{2}\times a \times 100\\\\\\\longrightarrow\sf S=a\times 50\\\\\\\longrightarrow\sf 200 = 50\;a \ \ \ \ \because \bigg(S=200\;m\bigg)\\\\\\\longrightarrow\sf a =\dfrac{200}{50}\\\\\\\longrightarrow\sf a=4\\\\\\\longrightarrow \large{\underline{\boxed{\red{\sf a=4\;m/s^{2}}}}}$

∴ The acceleration (a) is 4 m/s².

$\rule{300}{1.5}$

Answer 2

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$\huge\bold{\sf{\underline{\underline{\red{QUESTION}}}}}$

➡ A body starting from rest travels with uniform acceleration. If it travels 200 m in 10 s, then the

value of the acceleration is_______m/s.

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$\huge\bold{\sf{\underline{\underline{\red{ANSWER}}}}}$

❥ GIVEN :

Distance = 200 m

Time = 20 sec

Initial Velocity = 0 ( it is at rest )

❥ TO FIND :

Acceleration

❥ SOLUTION :

${\red\bigstar\large\bold{\mathrm{\underline{\green{Formula\:Used:}}}}}$

$\bold{\boxed{\sf{\pink{s\:=\:ut\:+\: \dfrac{1}{2}a{t}^{2}}}}}$

$\star\sf 200\:=\:0(20)\:+\: \dfrac{1}{2}(a) {10}^{2}$

$\star\sf 200\:=\:\dfrac{1}{2} \times 100a$

$\star\sf 200\:=\: 50a$

$\star\sf a\:=\: \dfrac{200}{50}$

${\red\bigstar\large\bold{\mathrm{\underline{\pink{Acceleration\:=\:4\:{m}^{2}}}}}}$

${\red\bigstar\large\bold{\mathrm{\underline{\green{KnOw\:MøRe:}}}}}$

✤ Other equation of motion :

1. $\sf v\:=\:u\:+\:at$
2. $\sf {v}^{2}\:-\:{u}^{2}\:=\:2as$

▶ NøTaTioNs -

v = final velocity

u = initial velocity

a = acceleration

s = distance covered

t = time taken

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