Question

A body starting from rest travels with uniform acceleration if the travels 100m in 5 seconds what is the value of acceleration

Answer 1

Given
Starting from rest so initial velocity =u= 0
Displacement=100m
Time=5s
So,final velocity = 100/5 = 20m/s
acceleration = a =( v-u)/t
= (20-0)/5 = 4m/s^2

Answer 2

The acceleration of the body is 8 m/s².

Explanation :

Given :

Initial velocity (u) = 0 m/s.

Distance (s) = 100 m.

Time (t) = 5 sec.

To Find :

The value of acceleration.

Solution :

We know that :

$\bigstar\;\boxed{\bf s= ut + \dfrac{1}{2}\;at^2}}$

So,

$\implies \sf 100 = 0(5) + \dfrac{1}{2} a(5)^2\\ \\ \\ \implies \sf 100 = \dfrac{1}{2} \times 25a\\ \\ \\\implies \sf 200 = 25a\\ \\ \\\implies \bf 8 = a$

Hence,

The acceleration of the body is 8 m/s².

$\rule{300}{1.5}$

• Acceleration :

Acceleration is the rate of change of velocity with time.

• Initial Velocity :

The velocity of the object before acceleration causes a change is called initial velocity.