Physics, asked by roses4626, 1 year ago

A body starting from rest travels with uniform acceleration if it travel 100m in 5s, what is he value of accelaration

Answers

Answered by mohanasiddharth
2

V=u+at

V=?

U=0m/s

t=5sec

V=0+a5

a=v/5


V^2-u^2=2as

V^2=2v100/5

V^2=40v

V=40m/s

a=v/5

a=40/5=8m/s^2


Answered by ButterFliee
3

Acceleration = 8 m/s²

Given:

  • Initial Velocity (u) of body = 0
  • Distance(s) travelled by body = 100m
  • Time taken(t) by body = 5 seconds

To Find :

  • What is the acceleration (a) of the body ?

Formula to be used :

  • Second equation of motion
  • S = ut + 1/2 ut²

Solution :

By using Second Law of motion, we can find the acceleration

On putting the values in the formula, we get

★ S = ut + 1/2 at² ★

\implies 100 = 0 \times 5 + 1/2 a(5)²

\implies 100 = 0 + a/2 \times 25

\implies100 = 25a/2

\implies 100 \times 2 = 25a

\implies 200 = 25a

\implies 200/25 = a

\implies 8 m/ = a

❛ Hence, the acceleration of the body is 8 m/s² 

_____________

Extra Information

First Equation of motion = v = u + at

Third Equation of motion = v² - u² = 2as

Acceleration = The rate of change of velocity with respect to particular time is known as acceleration.

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