A body starting from rest travels with uniform acceleration if it travel 100m in 5s, what is he value of accelaration
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Answered by
2
V=u+at
V=?
U=0m/s
t=5sec
V=0+a5
a=v/5
V^2-u^2=2as
V^2=2v100/5
V^2=40v
V=40m/s
a=v/5
a=40/5=8m/s^2
Answered by
3
★ Acceleration = 8 m/s²★
Given:
- Initial Velocity (u) of body = 0
- Distance(s) travelled by body = 100m
- Time taken(t) by body = 5 seconds
To Find :
- What is the acceleration (a) of the body ?
Formula to be used :
- Second equation of motion
- S = ut + 1/2 ut²
Solution :
By using Second Law of motion, we can find the acceleration
On putting the values in the formula, we get
★ S = ut + 1/2 at² ★
100 = 0 5 + 1/2 a(5)²
100 = 0 + a/2 25
100 = 25a/2
100 2 = 25a
200 = 25a
200/25 = a
8 m/s² = a
❛ Hence, the acceleration of the body is 8 m/s² ❜
_____________
✪ Extra Information ✪
➤ First Equation of motion = v = u + at
➤ Third Equation of motion = v² - u² = 2as
➤ Acceleration = The rate of change of velocity with respect to particular time is known as acceleration.
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