Question

A body starting from rest travels with uniform acceleration if it travel 100m in 5s, what is he value of accelaration

Answer 1

V=u+at

V=?

U=0m/s

t=5sec

V=0+a5

a=v/5

V^2-u^2=2as

V^2=2v100/5

V^2=40v

V=40m/s

a=v/5

a=40/5=8m/s^2

Answer 2

★ Acceleration = 8 m/s²★

Given:

• Initial Velocity (u) of body = 0
• Distance(s) travelled by body = 100m
• Time taken(t) by body = 5 seconds

To Find :

• What is the acceleration (a) of the body ?

Formula to be used :

• Second equation of motion
• S = ut + 1/2 ut²

Solution :

By using Second Law of motion, we can find the acceleration

On putting the values in the formula, we get

★ S = ut + 1/2 at² ★

$\implies$ 100 = 0 $\times$ 5 + 1/2 a(5)²

$\implies$ 100 = 0 + a/2 $\times$ 25

$\implies$100 = 25a/2

$\implies$ 100 $\times$ 2 = 25a

$\implies$ 200 = 25a

$\implies$ 200/25 = a

$\implies$ 8 m/s² = a

❛ Hence, the acceleration of the body is 8 m/s² ❜

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✪ Extra Information ✪

➤ First Equation of motion = v = u + at

➤ Third Equation of motion = v² - u² = 2as

➤ Acceleration = The rate of change of velocity with respect to particular time is known as acceleration.