Question

A body starting from rest travling with uniform acceleration has velocity of 40m/s after 10 sec at a velocity of the body 4 sec before it crosess the point a

Answer 1

given

u=0,as it is starting from rest

v=40ms

t=10 sec

from using the equation v=u+at

40=o+a10

40=10a- (eq-1)

now the time at which the velocity is asked to calculate is 6 sec as it reaches point a at 10 sec 4 sec before it means 6 sec,then applying the same equation

v=u+at

v=0+6a

v=6a

a=v/6-(eq2)

now substitute in eq 1

40=10×v/6

v=240/10

v=24 m/s