Question

A body starting from rest with uniform acceleration of 8 ms 2. The speed of the body after 5 s will be​

Answer 1

Answer:

Given that,

The acceleration a=8m/s

2

Initial velocity u=0m/s

We know that,

The displacement in the nth second

=u+a(n−

2

1

)

Now, the displacement in 5th second

=0+8(5−

2

1

)

=36m

Hence, the distance covered by it in fifth second is 36 m

Answer 2

Answer:

Explanation:

In this question, given data is

u(Initial velocity)=0ms-1

a(acceleration)=8ms-2

t(Time)=5s

From the formula v=u+a*t,

v=0+8*5

=>v=40ms-1

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