A body starting from rests a distance of 200 m in 10 seconds. Calculate the value of its
acceleration.
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Explanation:
The initial velocity travelled is 625m
The accleration is α=10m/s2
The time is t=5s
Apply the equation of motion
v=u+at
The velocity is v=0+10.5=50m/s.
The distance travelled in the first 5s is
s=ut+21at2=0.5+21.10.52=125mThedistancetravelledinthefollowing10siss1=ut1=50.10=500mThetotaldistancetravelledisd=s+s1=125+500=625m
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