Question

a body starting from the rest moves with a uniform acceleration of 0.02m/s from 5minutes calculate the speed acquired and the distance travelled in this time​

Answer 1

Answer:

The required speed is 6 m/s and distance travelled is 900 m.

Explanation:

Given :

Acceleration, a = 0.02 m/s²

initial velocity, u = 0 m/s

time, t = 5 min = 5 × 60 s = 300 s

To find :

the speed acquired and the distance travelled in this time.

Solution :

Using first equation of motion,

v = u + at

Substituting,

v = 0 + 0.02(300)

v = 6 m/s

Hence, the speed acquired is 6 m/s.

Now, applying second equation of motion.

S = ut + ½at²

S = 0(300) + ½(0.02)(300²)

S = 0 + 0.01 (90000)

S = 900 m

Therefore, the distance travelled in this time is 900 m.