Question

a body starting from the rest moves with a uniform acceleration of 0.02 m/s² for 5 minutes. calculate the speed acquired and the distance travelled in this time.​

Answer 1

$\huge\boxed{\mathtt\red{Solution :-}}$

Given :-

• The body starts from rest.
• The acceleration of the body is 0.02 m/s²
• Time is 5 minutes = (5×60) s = 300 s

To Find :-

• Velocity (speed) acquired by the body.
• Displacement (distance) made by the body.

Solution :-

⟹ Initial Velocity (u) = 0

because, the body starts from rest.

we know that :-

$\large\boxed{\mathtt\blue{v = u+at}}$

where,

• v = final velocity

• u = initial velocity

• a = acceleration

• t = time

⟹ v = 0 + (0.02 m/s² × 300s)

∴ v = 6 m/s

Applying the third formula of motion :-

$\large\boxed{\mathtt\blue{v²-u²= 2ad}}$

where,

• v = final velocity

• u = initial velocity

• a = acceleration

• d = displacement

⟹ (6 m/s)²-(0)² = 2×0.02m/s²×d

✒ 36 m²/s² = 0.04 m/s² ×d

∴ d = $\large{\mathtt{900\:m}}$

Answer :-

$\small\boxed{\mathtt\green{∴velocity \:(speed)\: acquired \:by\: the\:body\:is\:6\:m/s)}}$

$\small\boxed{\mathtt\green{∴Displacement (distance)\: covered\: by\:the\:body\:is\:900\:m}}$