Question

A body starting with a velocity of 10 metre per second is accelerated uniformly for 60sec. If the velocity acquired in this interval is 250 metre per second. Find the acceleration and also distance travelled​

Answer 1

The above question is of Kinematics. Let's know the three equations of motion first of all,

v = u + at

s = ut + 1/2 at²

v² = u² + 2as

Here u is the initial velocity, v is the final velocity, a is the accleration, s is the distance travelled, t is the time taken.

GiveN:

u = 10 m/s

v = 250 m/s

t = 60 s

To FinD:

Accleration of the body?

Distance travelled by the body?

Step-by-step Explanation:

By using 1st equation of motion,

⇒ v = u + at

⇒ 250 = 10 + a(60)

⇒ 240 = 60a

⇒ a = 4 m/s²

Accleration of the body is 4 m/s² (Answer)

Now finding the distance travelled.

By using 2nd equation of motion,

⇒ s = ut + 1/2 at²

⇒ s = 10(60) + 1/2 (4)(60)²

⇒ s = 600 + 7200 m

⇒ s = 7800 m

Distance travelled by the body is 7800 m. (Answer)

Answer 2

Answer:

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